First derivation is: f ' = 16x^{3} + 12x^{2}  22x + 2 = 0 
(This curve is sketched by the red line) 
The solutions of first derivation will give us the extreme points 
which are at: x_{1} = 1.64, x_{2} = 0.1 x_{3} = 0.79 
In order to find if the points are a maximum or minimum we 
shall find the second derivation: f ''(x) = 48x^{2} + 24x  22 
Now substitute each extreme point to the second derivation: 
f '' (x_{1}) = 48 * (1.64)^{2} + 24 * (1.64)  22 = 67.7 
f '' (x_{2}) = 48 * 0.1^{2} + 24 * 0.1  22 = 19.1 
f '' (x_{2}) = 48 * 0.79^{2} + 24 * 0.79  22 = 26.9 
x_{1}  is a minimum, x_{2}  is a maximum, and x_{3}  is a minimum 

